Factorise, then set each bracket to zero
What you will learn
Know the rule, then use it
These are the short notes. Read each one, then check you can use it in the worked example below.
Method
Look for two numbers that MULTIPLY to c and ADD to b in x2 + bx + c
Make sure one side equals zero
The equation is already x2 + 5x + 6 = 0
Find a pair of numbers that multiply to 6 and add to 5
Pairs: (1, 6) sum 7 — no
Write the factorised form
(x + 2)(x + 3) = 0
Watch out
Students find a pair that multiplies correctly but add incorrectly (for example 1 × 6 = 6 but 1 + 6 = 7 ≠ 5)
If AB = 0, then A = 0 or B = 0.
Solve x2 + 5x + 6 = 0 by factorising.
Make sure one side equals zero: The equation is already x2 + 5x + 6 = 0. If it were not, rearrange first.
Find a pair of numbers that multiply to 6 and add to 5: Pairs: (1, 6) sum 7 — no. (2, 3) sum 5 — yes. Use 2 and 3.
Write the factorised form: (x + 2)(x + 3) = 0
Apply the zero-product property: x + 2 = 0 → x = −2, or x + 3 = 0 → x = −3. Both solutions must be stated.
x = −2 or x = −3
Build up to the hardest questions
Do them in order. If you miss a step, read the solution, then redo the question without looking.
WorkedreasoningSolve x2 + 5x + 6 = 0 by factorising.
4 marks4 minssolving-quadratics-by-factorising-workedShow solution
Solve x2 + 5x + 6 = 0 by factorising.
- 1.Make sure one side equals zero: The equation is already x2 + 5x + 6 = 0. If it were not, rearrange first.
- 2.Find a pair of numbers that multiply to 6 and add to 5: Pairs: (1, 6) sum 7 — no. (2, 3) sum 5 — yes. Use 2 and 3.
- 3.Write the factorised form: (x + 2)(x + 3) = 0
- 4.Apply the zero-product property: x + 2 = 0 → x = −2, or x + 3 = 0 → x = −3. Both solutions must be stated.
x = −2 or x = −3
- M1: make sure one side equals zero
- M1: find a pair of numbers that multiply to 6 and add to 5
- M1: write the factorised form
- M1: apply the zero-product property
- A1: x = −2 or x = −3
g. 1 × 6 = 6 but 1 + 6 = 7 ≠ 5). Always write the pair check explicitly.Also, ensure the equation equals zero — rearranging first is essential if it does not.
DiagnosticrecallSolve x2 + 7x + 12 = 0
1 mark2 minssolving-quadratics-by-factorising-q1Show solution
Solve x2 + 7x + 12 = 0
- 1.Spot the skill: Look for two numbers that MULTIPLY to c and ADD to b in x2 + bx + c.
- 2.Use the make sure one side equals zero stage first, then find a pair of numbers that multiply to 6 and add to 5.
- 3.Keep the final answer visible: x = −3 or x = −4.
x = −3 or x = −4
- M1: use the correct look for two numbers that multiply to c and add to b in x2 + bx + c.write as (x + p)(x + q) = 0, then set each bracket to zero.for 2ax2 + bx + c: multiply a by c, find two numbers multiplying to ac and adding to b, split the middle term.
- A1: x = −3 or x = −4
g. 1 × 6 = 6 but 1 + 6 = 7 ≠ 5). Always write the pair check explicitly.Also, ensure the equation equals zero — rearranging first is essential if it does not.
EasyprocedureSolve x2 − x − 6 = 0
2 marks3 minssolving-quadratics-by-factorising-q2Show solution
Solve x2 − x − 6 = 0
- 1.Spot the skill: Look for two numbers that MULTIPLY to c and ADD to b in x2 + bx + c.
- 2.Use the find a pair of numbers that multiply to 6 and add to 5 stage first, then write the factorised form.
- 3.Keep the final answer visible: x = 3 or x = −2.
x = 3 or x = −2
- M1: use the correct look for two numbers that multiply to c and add to b in x2 + bx + c.write as (x + p)(x + q) = 0, then set each bracket to zero.for 2ax2 + bx + c: multiply a by c, find two numbers multiplying to ac and adding to b, split the middle term.
- A1: x = 3 or x = −2
g. 1 × 6 = 6 but 1 + 6 = 7 ≠ 5). Always write the pair check explicitly.Also, ensure the equation equals zero — rearranging first is essential if it does not.
MediumreasoningSolve x2 − 9x + 18 = 0
3 marks4 minssolving-quadratics-by-factorising-q3Show solution
Solve x2 − 9x + 18 = 0
- 1.Spot the skill: Look for two numbers that MULTIPLY to c and ADD to b in x2 + bx + c.
- 2.Use the write the factorised form stage first, then apply the zero-product property.
- 3.Keep the final answer visible: x = 3 or x = 6.
x = 3 or x = 6
- M1: use the correct look for two numbers that multiply to c and add to b in x2 + bx + c.write as (x + p)(x + q) = 0, then set each bracket to zero.for 2ax2 + bx + c: multiply a by c, find two numbers multiplying to ac and adding to b, split the middle term.
- A1: x = 3 or x = 6
g. 1 × 6 = 6 but 1 + 6 = 7 ≠ 5). Always write the pair check explicitly.Also, ensure the equation equals zero — rearranging first is essential if it does not.
Hardproblem solvingSolve x2 − 25 = 0 by factorising (difference of two squares)
3 marks5 minssolving-quadratics-by-factorising-q4Show solution
Solve x2 − 25 = 0 by factorising (difference of two squares)
- 1.Spot the skill: Look for two numbers that MULTIPLY to c and ADD to b in x2 + bx + c.
- 2.Use the apply the zero-product property stage first, then make sure one side equals zero.
- 3.Keep the final answer visible: x = 5 or x = −5.
x = 5 or x = −5
- M1: use the correct look for two numbers that multiply to c and add to b in x2 + bx + c.write as (x + p)(x + q) = 0, then set each bracket to zero.for 2ax2 + bx + c: multiply a by c, find two numbers multiplying to ac and adding to b, split the middle term.
- A1: x = 5 or x = −5
g. 1 × 6 = 6 but 1 + 6 = 7 ≠ 5). Always write the pair check explicitly.Also, ensure the equation equals zero — rearranging first is essential if it does not.
Exam-stylemulti-stepSolve 2x2 + 7x + 3 = 0
4 marks6 minssolving-quadratics-by-factorising-q5Show solution
Solve 2x2 + 7x + 3 = 0
- 1.Spot the skill: Look for two numbers that MULTIPLY to c and ADD to b in x2 + bx + c.
- 2.Use the make sure one side equals zero stage first, then find a pair of numbers that multiply to 6 and add to 5.
- 3.Keep the final answer visible: x = − or x = −3.
x = − or x = −3
- M1: use the correct look for two numbers that multiply to c and add to b in x2 + bx + c.write as (x + p)(x + q) = 0, then set each bracket to zero.for 2ax2 + bx + c: multiply a by c, find two numbers multiplying to ac and adding to b, split the middle term.
- A1: x = − or x = −3
g. 1 × 6 = 6 but 1 + 6 = 7 ≠ 5). Always write the pair check explicitly.Also, ensure the equation equals zero — rearranging first is essential if it does not.
Grade 9 stretchproblem solvingSolve 2x2 - 7x + 3 = 0.
4 marks7 minsquad-factor-g9Show solution
Solve 2x2 - 7x + 3 = 0.
- 1.Find factors that create the middle term.
- 2.Factorise as two brackets.
- 3.Set each bracket equal to zero.
x = 3 or x =
- M1: (2x - 1)(x - 3)
- A1: both solutions
Do not rush straight into arithmetic. Select the relevant method and show a complete chain of working.
Switch between skills
Set a timer and attempt all four questions before opening any answers. This is closer to the way skills appear in a real paper.
1Solving quadratics by factorising - 2 marksSolve x2 + 7x + 12 = 0Mark answer
x = −3 or x = −4
2Algebraic notation and substitution - 2 marksFind t² + 4t when t = −2Mark answer
−4
3Simplifying expressions - 2 marksSimplify 2xy + 3x²y − xy + x²yMark answer
3x²y + xy
4Expanding and factorising - 3 marksFactorise fully 6x² + 9xMark answer
3x(2x + 3)
- I can explain the method for solving quadratics by factorising.
- I can show clear working without skipping key steps.
- g. 1 × 6 = 6 but 1 + 6 = 7 ≠ 5). Always write the pair check explicitly.Also, ensure the equation equals zero — rearranging first is essential if it does not.
This guide follows the Pearson Edexcel GCSE Mathematics 1MA1 specification. Practice questions are original Learnova questions shaped around official content and exam skills.