Quadratic formula and completing the square

Solve quadratics that do not factorise easily.

Pearson EdexcelGCSE MathsAlgebraHigher
Visual model

Use the formula when factorising is not obvious

ax2+bx+c=0ax^{2} + bx + c = 0x=b±b24ac2ax = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}identify a, b and c before substituting
Gold-standard guide
26 mins

What you will learn

Solve quadratics that do not factorise easily.
Use a clear step-by-step method for quadratic formula and completing the square.
Check your answer and avoid the most common exam mistake.
Useful before you start
Core number skillsEarlier algebra skillsShowing clear working
Core knowledge

Know the rule, then use it

These are the short notes. Read each one, then check you can use it in the worked example below.

Method

Method

Quadratic formula: x = (−b ± b24ac\sqrt{b^{2} − 4ac}) / 2a

Step 1

Identify a, b and c

a = 1, b = 6, c = 2

Step 2

Calculate the discriminant b^2 − 4ac

62 − 4(1)(2) = 36 − 8 = 28

Step 3

Substitute into the formula

x = (−6 ± 28\sqrt{28}) / 2

Watch out

Watch out

Students forget to simplify the surd at the end, leaving 28\sqrt{28} unresolved

f
Quadratic formula

x=(b±b24ac)/2a.x = (-b \pm \sqrt{b^{2} - 4ac}) / 2a.

f
Complete square

x2+bx=(x+b2)2(b2)2.x^{2} + bx = (x + \frac{b}{2})^{2} - (\frac{b}{2})^{2}.

Worked example

Solve x2 + 6x + 2 = 0, giving your answers in surd form.

1

Identify a, b and c: a = 1, b = 6, c = 2.

2

Calculate the discriminant b2 − 4ac: 62 − 4(1)(2) = 36 − 8 = 28.

3

Substitute into the formula: x = (−6 ± 28\sqrt{28}) / 2.

4

Simplify the surd: 28\sqrt{28} = 4×7\sqrt{4 \times 7} = 2sqrt(7). So x = (−6 ± 2sqrt(7)) / 2 = −3 ± 7\sqrt{7}.

Final answer

x = −3 + 7\sqrt{7} or x = −3 − 7\sqrt{7}

Question ladder

Build up to the hardest questions

Do them in order. If you miss a step, read the solution, then redo the question without looking.

Workedreasoning

Solve x2 + 6x + 2 = 0, giving your answers in surd form.

4 marks4 minsquadratic-formula-and-completing-the-square-worked
Show solution
Worked solution
  1. 1.Identify a, b and c: a = 1, b = 6, c = 2.
  2. 2.Calculate the discriminant b2 − 4ac: 62 − 4(1)(2) = 36 − 8 = 28.
  3. 3.Substitute into the formula: x = (−6 ± 28\sqrt{28}) / 2.
  4. 4.Simplify the surd: 28\sqrt{28} = 4×7\sqrt{4 \times 7} = 2sqrt(7). So x = (−6 ± 2sqrt(7)) / 2 = −3 ± 7\sqrt{7}.
Final answer

x = −3 + 7\sqrt{7} or x = −3 − 7\sqrt{7}

Mark points
  • M1: identify a, b and c
  • M1: calculate the discriminant b2 − 4ac
  • M1: substitute into the formula
  • M1: simplify the surd
  • A1: x = −3 + 7\sqrt{7} or x = −3 − 7\sqrt{7}
Watch out

Students forget to simplify the surd at the end, leaving 28\sqrt{28} unresolved.Divide both the integer part and the surd by any common factor.Also, the formula uses −b, so a positive b gives a negative numerator — watch the signs.

Diagnosticrecall

Use the formula to solve x2 − 4x + 1 = 0. Leave in surd form.

1 mark2 minsquadratic-formula-and-completing-the-square-q1
Show solution
Worked solution
  1. 1.Spot the skill: Quadratic formula: x = (−b ± b24ac\sqrt{b^{2} − 4ac}) / 2a.
  2. 2.Use the identify a, b and c stage first, then calculate the discriminant b2 − 4ac.
  3. 3.Keep the final answer visible: x = 2 ± 3\sqrt{3}.
Final answer

x = 2 ± 3\sqrt{3}

Mark points
  • M1: use the correct quadratic formula: x = (−b ± b24ac\sqrt{b^{2} − 4ac}) / 2a. use it when the quadratic does not factorise.completing the square rewrites ax2 + bx + c as a(x + p)2 + q and directly gives the turning point (−p, q).
  • A1: x = 2 ± 3\sqrt{3}
Watch out

Students forget to simplify the surd at the end, leaving 28\sqrt{28} unresolved.Divide both the integer part and the surd by any common factor.Also, the formula uses −b, so a positive b gives a negative numerator — watch the signs.

Easyprocedure

Complete the square for x2 − 8x + 3, writing in the form (x + a)2 + b.

2 marks3 minsquadratic-formula-and-completing-the-square-q2
Show solution
Worked solution
  1. 1.Spot the skill: Quadratic formula: x = (−b ± b24ac\sqrt{b^{2} − 4ac}) / 2a.
  2. 2.Use the calculate the discriminant b2 − 4ac stage first, then substitute into the formula.
  3. 3.Keep the final answer visible: (x − 4)2 − 13.
Final answer

(x − 4)2 − 13

Mark points
  • M1: use the correct quadratic formula: x = (−b ± b24ac\sqrt{b^{2} − 4ac}) / 2a. use it when the quadratic does not factorise.completing the square rewrites ax2 + bx + c as a(x + p)2 + q and directly gives the turning point (−p, q).
  • A1: (x − 4)2 − 13
Watch out

Students forget to simplify the surd at the end, leaving 28\sqrt{28} unresolved.Divide both the integer part and the surd by any common factor.Also, the formula uses −b, so a positive b gives a negative numerator — watch the signs.

Mediumreasoning

Find the turning point of y = x2 + 10x + 18 by completing the square.

3 marks4 minsquadratic-formula-and-completing-the-square-q3
Show solution
Worked solution
  1. 1.Spot the skill: Quadratic formula: x = (−b ± b24ac\sqrt{b^{2} − 4ac}) / 2a.
  2. 2.Use the substitute into the formula stage first, then simplify the surd.
  3. 3.Keep the final answer visible: (−5, −7).
Final answer

(−5, −7)

Mark points
  • M1: use the correct quadratic formula: x = (−b ± b24ac\sqrt{b^{2} − 4ac}) / 2a. use it when the quadratic does not factorise.completing the square rewrites ax2 + bx + c as a(x + p)2 + q and directly gives the turning point (−p, q).
  • A1: (−5, −7)
Watch out

Students forget to simplify the surd at the end, leaving 28\sqrt{28} unresolved.Divide both the integer part and the surd by any common factor.Also, the formula uses −b, so a positive b gives a negative numerator — watch the signs.

Hardproblem solving

Show that x2 + x + 1 = 0 has no real solutions.

3 marks5 minsquadratic-formula-and-completing-the-square-q4
Show solution
Worked solution
  1. 1.Spot the skill: Quadratic formula: x = (−b ± b24ac\sqrt{b^{2} − 4ac}) / 2a.
  2. 2.Use the simplify the surd stage first, then identify a, b and c.
  3. 3.Keep the final answer visible: Discriminant = 1 − 4 = −3 < 0, no real solutions.
Final answer

Discriminant = 1 − 4 = −3 < 0, no real solutions

Mark points
  • M1: use the correct quadratic formula: x = (−b ± b24ac\sqrt{b^{2} − 4ac}) / 2a. use it when the quadratic does not factorise.completing the square rewrites ax2 + bx + c as a(x + p)2 + q and directly gives the turning point (−p, q).
  • A1: Discriminant = 1 − 4 = −3 < 0, no real solutions
Watch out

Students forget to simplify the surd at the end, leaving 28\sqrt{28} unresolved.Divide both the integer part and the surd by any common factor.Also, the formula uses −b, so a positive b gives a negative numerator — watch the signs.

Exam-stylemulti-step

Solve 3x2 − 5x − 2 = 0 using the formula.

4 marks6 minsquadratic-formula-and-completing-the-square-q5
Show solution
Worked solution
  1. 1.Spot the skill: Quadratic formula: x = (−b ± b24ac\sqrt{b^{2} − 4ac}) / 2a.
  2. 2.Use the identify a, b and c stage first, then calculate the discriminant b2 − 4ac.
  3. 3.Keep the final answer visible: x = 2 or x = −13\frac{1}{3}.
Final answer

x = 2 or x = −13\frac{1}{3}

Mark points
  • M1: use the correct quadratic formula: x = (−b ± b24ac\sqrt{b^{2} − 4ac}) / 2a. use it when the quadratic does not factorise.completing the square rewrites ax2 + bx + c as a(x + p)2 + q and directly gives the turning point (−p, q).
  • A1: x = 2 or x = −13\frac{1}{3}
Watch out

Students forget to simplify the surd at the end, leaving 28\sqrt{28} unresolved.Divide both the integer part and the surd by any common factor.Also, the formula uses −b, so a positive b gives a negative numerator — watch the signs.

Grade 9 stretchproblem solving

The graph y = x2 - 6x + 1 crosses the x-axis at A and B. Find the exact x-coordinates of A and B, then find the minimum point of the graph.

4 marks7 minsquad-formula-g9
Show solution
Worked solution
  1. 1.Use the quadratic formula to solve x2 - 6x + 1 = 0 exactly.
  2. 2.Complete the square to locate the turning point.
  3. 3.State both roots and the minimum as a coordinate.
Final answer

A and B have x-coordinates 3 - 2sqrt(2) and 3 + 2sqrt(2); the minimum point is (3, -8)

Mark points
  • M1: substitute a = 1, b = -6, c = 1 into the formula
  • A1: simplify the roots to 3 ± 2sqrt(2)
  • M1: write y = (x - 3)2 - 8
  • A1: state the minimum point (3, -8)
Watch out

Do not rush straight into arithmetic. Select the relevant method and show a complete chain of working.

Timed checkpoint
16 mins - 9 marks

Switch between skills

Set a timer and attempt all four questions before opening any answers. This is closer to the way skills appear in a real paper.

1Quadratic formula and completing the square - 2 marksUse the formula to solve x2 − 4x + 1 = 0. Leave in surd form.Mark answer
Answer

x = 2 ± 3\sqrt{3}

2Algebraic notation and substitution - 2 marksFind t² + 4t when t = −2Mark answer
Answer

−4

3Simplifying expressions - 2 marksSimplify 2xy + 3x²y − xy + x²yMark answer
Answer

3x²y + xy

4Expanding and factorising - 3 marksFactorise fully 6x² + 9xMark answer
Answer

3x(2x + 3)

Mastery check
  • I can explain the method for quadratic formula and completing the square.
  • I can show clear working without skipping key steps.
  • I can avoid this mistake: Students forget to simplify the surd at the end, leaving 28\sqrt{28} unresolved.Divide both the integer part and the surd by any common factor.Also, the formula uses −b, so a positive b gives a negative numerator — watch the signs.
Related topics
Official exam-board sources

This guide follows the Pearson Edexcel GCSE Mathematics 1MA1 specification. Practice questions are original Learnova questions shaped around official content and exam skills.

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