Use the formula when factorising is not obvious
What you will learn
Know the rule, then use it
These are the short notes. Read each one, then check you can use it in the worked example below.
Method
Quadratic formula: x = (−b ± ) / 2a
Identify a, b and c
a = 1, b = 6, c = 2
Calculate the discriminant b^2 − 4ac
62 − 4(1)(2) = 36 − 8 = 28
Substitute into the formula
x = (−6 ± ) / 2
Watch out
Students forget to simplify the surd at the end, leaving unresolved
Solve x2 + 6x + 2 = 0, giving your answers in surd form.
Identify a, b and c: a = 1, b = 6, c = 2.
Calculate the discriminant b2 − 4ac: 62 − 4(1)(2) = 36 − 8 = 28.
Substitute into the formula: x = (−6 ± ) / 2.
Simplify the surd: = = 2sqrt(7). So x = (−6 ± 2sqrt(7)) / 2 = −3 ± .
x = −3 + or x = −3 −
Build up to the hardest questions
Do them in order. If you miss a step, read the solution, then redo the question without looking.
WorkedreasoningSolve x2 + 6x + 2 = 0, giving your answers in surd form.
4 marks4 minsquadratic-formula-and-completing-the-square-workedShow solution
Solve x2 + 6x + 2 = 0, giving your answers in surd form.
- 1.Identify a, b and c: a = 1, b = 6, c = 2.
- 2.Calculate the discriminant b2 − 4ac: 62 − 4(1)(2) = 36 − 8 = 28.
- 3.Substitute into the formula: x = (−6 ± ) / 2.
- 4.Simplify the surd: = = 2sqrt(7). So x = (−6 ± 2sqrt(7)) / 2 = −3 ± .
x = −3 + or x = −3 −
- M1: identify a, b and c
- M1: calculate the discriminant b2 − 4ac
- M1: substitute into the formula
- M1: simplify the surd
- A1: x = −3 + or x = −3 −
Students forget to simplify the surd at the end, leaving unresolved.Divide both the integer part and the surd by any common factor.Also, the formula uses −b, so a positive b gives a negative numerator — watch the signs.
DiagnosticrecallUse the formula to solve x2 − 4x + 1 = 0. Leave in surd form.
1 mark2 minsquadratic-formula-and-completing-the-square-q1Show solution
Use the formula to solve x2 − 4x + 1 = 0. Leave in surd form.
- 1.Spot the skill: Quadratic formula: x = (−b ± ) / 2a.
- 2.Use the identify a, b and c stage first, then calculate the discriminant b2 − 4ac.
- 3.Keep the final answer visible: x = 2 ± .
x = 2 ±
- M1: use the correct quadratic formula: x = (−b ± ) / 2a. use it when the quadratic does not factorise.completing the square rewrites ax2 + bx + c as a(x + p)2 + q and directly gives the turning point (−p, q).
- A1: x = 2 ±
Students forget to simplify the surd at the end, leaving unresolved.Divide both the integer part and the surd by any common factor.Also, the formula uses −b, so a positive b gives a negative numerator — watch the signs.
EasyprocedureComplete the square for x2 − 8x + 3, writing in the form (x + a)2 + b.
2 marks3 minsquadratic-formula-and-completing-the-square-q2Show solution
Complete the square for x2 − 8x + 3, writing in the form (x + a)2 + b.
- 1.Spot the skill: Quadratic formula: x = (−b ± ) / 2a.
- 2.Use the calculate the discriminant b2 − 4ac stage first, then substitute into the formula.
- 3.Keep the final answer visible: (x − 4)2 − 13.
(x − 4)2 − 13
- M1: use the correct quadratic formula: x = (−b ± ) / 2a. use it when the quadratic does not factorise.completing the square rewrites ax2 + bx + c as a(x + p)2 + q and directly gives the turning point (−p, q).
- A1: (x − 4)2 − 13
Students forget to simplify the surd at the end, leaving unresolved.Divide both the integer part and the surd by any common factor.Also, the formula uses −b, so a positive b gives a negative numerator — watch the signs.
MediumreasoningFind the turning point of y = x2 + 10x + 18 by completing the square.
3 marks4 minsquadratic-formula-and-completing-the-square-q3Show solution
Find the turning point of y = x2 + 10x + 18 by completing the square.
- 1.Spot the skill: Quadratic formula: x = (−b ± ) / 2a.
- 2.Use the substitute into the formula stage first, then simplify the surd.
- 3.Keep the final answer visible: (−5, −7).
(−5, −7)
- M1: use the correct quadratic formula: x = (−b ± ) / 2a. use it when the quadratic does not factorise.completing the square rewrites ax2 + bx + c as a(x + p)2 + q and directly gives the turning point (−p, q).
- A1: (−5, −7)
Students forget to simplify the surd at the end, leaving unresolved.Divide both the integer part and the surd by any common factor.Also, the formula uses −b, so a positive b gives a negative numerator — watch the signs.
Hardproblem solvingShow that x2 + x + 1 = 0 has no real solutions.
3 marks5 minsquadratic-formula-and-completing-the-square-q4Show solution
Show that x2 + x + 1 = 0 has no real solutions.
- 1.Spot the skill: Quadratic formula: x = (−b ± ) / 2a.
- 2.Use the simplify the surd stage first, then identify a, b and c.
- 3.Keep the final answer visible: Discriminant = 1 − 4 = −3 < 0, no real solutions.
Discriminant = 1 − 4 = −3 < 0, no real solutions
- M1: use the correct quadratic formula: x = (−b ± ) / 2a. use it when the quadratic does not factorise.completing the square rewrites ax2 + bx + c as a(x + p)2 + q and directly gives the turning point (−p, q).
- A1: Discriminant = 1 − 4 = −3 < 0, no real solutions
Students forget to simplify the surd at the end, leaving unresolved.Divide both the integer part and the surd by any common factor.Also, the formula uses −b, so a positive b gives a negative numerator — watch the signs.
Exam-stylemulti-stepSolve 3x2 − 5x − 2 = 0 using the formula.
4 marks6 minsquadratic-formula-and-completing-the-square-q5Show solution
Solve 3x2 − 5x − 2 = 0 using the formula.
- 1.Spot the skill: Quadratic formula: x = (−b ± ) / 2a.
- 2.Use the identify a, b and c stage first, then calculate the discriminant b2 − 4ac.
- 3.Keep the final answer visible: x = 2 or x = −.
x = 2 or x = −
- M1: use the correct quadratic formula: x = (−b ± ) / 2a. use it when the quadratic does not factorise.completing the square rewrites ax2 + bx + c as a(x + p)2 + q and directly gives the turning point (−p, q).
- A1: x = 2 or x = −
Students forget to simplify the surd at the end, leaving unresolved.Divide both the integer part and the surd by any common factor.Also, the formula uses −b, so a positive b gives a negative numerator — watch the signs.
Grade 9 stretchproblem solvingThe graph y = x2 - 6x + 1 crosses the x-axis at A and B. Find the exact x-coordinates of A and B, then find the minimum point of the graph.
4 marks7 minsquad-formula-g9Show solution
The graph y = x2 - 6x + 1 crosses the x-axis at A and B. Find the exact x-coordinates of A and B, then find the minimum point of the graph.
- 1.Use the quadratic formula to solve x2 - 6x + 1 = 0 exactly.
- 2.Complete the square to locate the turning point.
- 3.State both roots and the minimum as a coordinate.
A and B have x-coordinates 3 - 2sqrt(2) and 3 + 2sqrt(2); the minimum point is (3, -8)
- M1: substitute a = 1, b = -6, c = 1 into the formula
- A1: simplify the roots to 3 ± 2sqrt(2)
- M1: write y = (x - 3)2 - 8
- A1: state the minimum point (3, -8)
Do not rush straight into arithmetic. Select the relevant method and show a complete chain of working.
Switch between skills
Set a timer and attempt all four questions before opening any answers. This is closer to the way skills appear in a real paper.
1Quadratic formula and completing the square - 2 marksUse the formula to solve x2 − 4x + 1 = 0. Leave in surd form.Mark answer
x = 2 ±
2Algebraic notation and substitution - 2 marksFind t² + 4t when t = −2Mark answer
−4
3Simplifying expressions - 2 marksSimplify 2xy + 3x²y − xy + x²yMark answer
3x²y + xy
4Expanding and factorising - 3 marksFactorise fully 6x² + 9xMark answer
3x(2x + 3)
- I can explain the method for quadratic formula and completing the square.
- I can show clear working without skipping key steps.
- I can avoid this mistake: Students forget to simplify the surd at the end, leaving unresolved.Divide both the integer part and the surd by any common factor.Also, the formula uses −b, so a positive b gives a negative numerator — watch the signs.
This guide follows the AQA GCSE Mathematics 8300 specification. Practice questions are original Learnova questions shaped around official content and exam skills.