AQA MathsAlgebra

Quadratic and geometric sequences

Recognise and continue more complex patterns.

AQAGCSE MathsAlgebraHigher
Visual model

Quadratic sequences have constant second differences

11449916162525+3+3+5+5+7+7+9+9second differences stay constant
Gold-standard guide
26 mins

What you will learn

Recognise and continue more complex patterns.
Use a clear step-by-step method for quadratic and geometric sequences.
Check your answer and avoid the most common exam mistake.
Useful before you start
Core number skillsEarlier algebra skillsShowing clear working
Core knowledge

Know the rule, then use it

These are the short notes. Read each one, then check you can use it in the worked example below.

Method

Method

For quadratic sequences, the first differences change but the second differences are constant

Step 1

Find first and second differences

First differences: 6, 10, 14, 18

Step 2

Find the coefficient a

Second difference = 2a = 4, so a = 2

Step 3

Subtract 2n² from the sequence to find the linear remainder

2n² gives: 2, 8, 18, 32, 50

Watch out

Watch out

Students try to use a linear nth-term method on a quadratic sequence, finding a different step each time and getting confused

f
Quadratic sequence

Constant second difference means an2 + bn + c.

f
Geometric sequence

Multiply by the same ratio each time.

Worked example

A quadratic sequence begins 3, 9, 19, 33, 51, ... Find the nth term.

1

Find first and second differences: First differences: 6, 10, 14, 18. Second differences: 4, 4, 4.The constant second difference confirms this is quadratic.

2

Find the coefficient a: Second difference = 2a = 4, so a = 2. The nth term starts with 2n².

3

Subtract 2n² from the sequence to find the linear remainder: 2n² gives: 2, 8, 18, 32, 50.Subtracting: 3−2=1, 9−8=1, 19−18=1, 33−32=1. The remainder is the constant sequence 1. So the linear part is 0n + 1.

4

Write the full nth term: T(n) = 2n² + 0n + 1 = 2n² + 1. Check: T(1) = 3 ✓, T(4) = 33 ✓.

Final answer

T(n) = 2n² + 1

Question ladder

Build up to the hardest questions

Do them in order. If you miss a step, read the solution, then redo the question without looking.

Workedreasoning

A quadratic sequence begins 3, 9, 19, 33, 51, ... Find the nth term.

4 marks4 minsquadratic-and-geometric-sequences-worked
Show solution
Worked solution
  1. 1.Find first and second differences: First differences: 6, 10, 14, 18. Second differences: 4, 4, 4.The constant second difference confirms this is quadratic.
  2. 2.Find the coefficient a: Second difference = 2a = 4, so a = 2. The nth term starts with 2n².
  3. 3.Subtract 2n² from the sequence to find the linear remainder: 2n² gives: 2, 8, 18, 32, 50.Subtracting: 3−2=1, 9−8=1, 19−18=1, 33−32=1. The remainder is the constant sequence 1. So the linear part is 0n + 1.
  4. 4.Write the full nth term: T(n) = 2n² + 0n + 1 = 2n² + 1. Check: T(1) = 3 ✓, T(4) = 33 ✓.
Final answer

T(n) = 2n² + 1

Mark points
  • M1: find first and second differences
  • M1: find the coefficient a
  • M1: subtract 2n² from the sequence to find the linear remainder
  • M1: write the full nth term
  • A1: T(n) = 2n² + 1
Watch out

Students try to use a linear nth-term method on a quadratic sequence, finding a different step each time and getting confused.The diagnostic test is always to check second differences first. If they are constant, the sequence is quadratic.If first differences are constant, it is linear.If second differences are also changing, check for geometric (constant ratio) or other patterns.

Diagnosticrecall

Find the next two terms of the geometric sequence 5, 10, 20, 40, ...

1 mark2 minsquadratic-and-geometric-sequences-q1
Show solution
Worked solution
  1. 1.Spot the skill: For quadratic sequences, the first differences change but the second differences are constant.
  2. 2.Use the find first and second differences stage first, then find the coefficient a.
  3. 3.Keep the final answer visible: 80, 160.
Final answer

80, 160

Mark points
  • M1: use the correct for quadratic sequences, the first differences change but the second differences are constant.the second difference equals 2a, where t(n) = an² + bn + c.find a from the second difference, then use simultaneous equations to find b and c.
  • A1: 80, 160
Watch out

Students try to use a linear nth-term method on a quadratic sequence, finding a different step each time and getting confused.The diagnostic test is always to check second differences first. If they are constant, the sequence is quadratic.If first differences are constant, it is linear.If second differences are also changing, check for geometric (constant ratio) or other patterns.

Easyprocedure

Find the nth term of the geometric sequence 3, 6, 12, 24, ...

2 marks3 minsquadratic-and-geometric-sequences-q2
Show solution
Worked solution
  1. 1.Spot the skill: For quadratic sequences, the first differences change but the second differences are constant.
  2. 2.Use the find the coefficient a stage first, then subtract 2n² from the sequence to find the linear remainder.
  3. 3.Keep the final answer visible: 3 × 2^(n−1).
Final answer

3 × 2^(n−1)

Mark points
  • M1: use the correct for quadratic sequences, the first differences change but the second differences are constant.the second difference equals 2a, where t(n) = an² + bn + c.find a from the second difference, then use simultaneous equations to find b and c.
  • A1: 3 × 2^(n−1)
Watch out

Students try to use a linear nth-term method on a quadratic sequence, finding a different step each time and getting confused.The diagnostic test is always to check second differences first. If they are constant, the sequence is quadratic.If first differences are constant, it is linear.If second differences are also changing, check for geometric (constant ratio) or other patterns.

Mediumreasoning

Find the second differences of 1, 5, 11, 19, 29 and hence find the nth term

3 marks4 minsquadratic-and-geometric-sequences-q3
Show solution
Worked solution
  1. 1.Spot the skill: For quadratic sequences, the first differences change but the second differences are constant.
  2. 2.Use the subtract 2n² from the sequence to find the linear remainder stage first, then write the full nth term.
  3. 3.Keep the final answer visible: Second diff = 2, so a=1; T(n) = n² + n − 1.
Final answer

Second diff = 2, so a=1; T(n) = n² + n − 1

Mark points
  • M1: use the correct for quadratic sequences, the first differences change but the second differences are constant.the second difference equals 2a, where t(n) = an² + bn + c.find a from the second difference, then use simultaneous equations to find b and c.
  • A1: Second diff = 2, so a=1; T(n) = n² + n − 1
Watch out

Students try to use a linear nth-term method on a quadratic sequence, finding a different step each time and getting confused.The diagnostic test is always to check second differences first. If they are constant, the sequence is quadratic.If first differences are constant, it is linear.If second differences are also changing, check for geometric (constant ratio) or other patterns.

Hardproblem solving

A quadratic sequence has nth term n² − 2n + 3. Find the first term that exceeds 50.

3 marks5 minsquadratic-and-geometric-sequences-q4
Show solution
Worked solution
  1. 1.Spot the skill: For quadratic sequences, the first differences change but the second differences are constant.
  2. 2.Use the write the full nth term stage first, then find first and second differences.
  3. 3.Keep the final answer visible: T(8) = 64 − 16 + 3 = 51.
Final answer

T(8) = 64 − 16 + 3 = 51

Mark points
  • M1: use the correct for quadratic sequences, the first differences change but the second differences are constant.the second difference equals 2a, where t(n) = an² + bn + c.find a from the second difference, then use simultaneous equations to find b and c.
  • A1: T(8) = 64 − 16 + 3 = 51
Watch out

Students try to use a linear nth-term method on a quadratic sequence, finding a different step each time and getting confused.The diagnostic test is always to check second differences first. If they are constant, the sequence is quadratic.If first differences are constant, it is linear.If second differences are also changing, check for geometric (constant ratio) or other patterns.

Exam-stylemulti-step

A geometric sequence has first term 4 and common ratio 0.5. Find the 5th term.

4 marks6 minsquadratic-and-geometric-sequences-q5
Show solution
Worked solution
  1. 1.Spot the skill: For quadratic sequences, the first differences change but the second differences are constant.
  2. 2.Use the find first and second differences stage first, then find the coefficient a.
  3. 3.Keep the final answer visible: 0.25.
Final answer

0.25

Mark points
  • M1: use the correct for quadratic sequences, the first differences change but the second differences are constant.the second difference equals 2a, where t(n) = an² + bn + c.find a from the second difference, then use simultaneous equations to find b and c.
  • A1: 0.25
Watch out

Students try to use a linear nth-term method on a quadratic sequence, finding a different step each time and getting confused.The diagnostic test is always to check second differences first. If they are constant, the sequence is quadratic.If first differences are constant, it is linear.If second differences are also changing, check for geometric (constant ratio) or other patterns.

Grade 9 stretchproblem solving

The nth term of a quadratic sequence is n2 + 3n - 1. Find the first term greater than 100.

4 marks7 minssequence-g9
Show solution
Worked solution
  1. 1.Solve n2 + 3n - 1 > 100.
  2. 2.Test nearby positive integer values.
Final answer

The 9th term, which is 107

Mark points
  • M1: form inequality
  • M1: test n = 8 and n = 9
  • A1: ninth term
Watch out

Do not rush straight into arithmetic. Select the relevant method and show a complete chain of working.

Timed checkpoint
16 mins - 9 marks

Switch between skills

Set a timer and attempt all four questions before opening any answers. This is closer to the way skills appear in a real paper.

1Quadratic and geometric sequences - 2 marksFind the next two terms of the geometric sequence 5, 10, 20, 40, ...Mark answer
Answer

80, 160

2Algebraic notation and substitution - 2 marksFind t² + 4t when t = −2Mark answer
Answer

−4

3Simplifying expressions - 2 marksSimplify 2xy + 3x²y − xy + x²yMark answer
Answer

3x²y + xy

4Expanding and factorising - 3 marksFactorise fully 6x² + 9xMark answer
Answer

3x(2x + 3)

Mastery check
  • I can explain the method for quadratic and geometric sequences.
  • I can show clear working without skipping key steps.
  • I can avoid this mistake: Students try to use a linear nth-term method on a quadratic sequence, finding a different step each time and getting confused.The diagnostic test is always to check second differences first. If they are constant, the sequence is quadratic.If first differences are constant, it is linear.If second differences are also changing, check for geometric (constant ratio) or other patterns.
Related topics
Official exam-board sources

This guide follows the AQA GCSE Mathematics 8300 specification. Practice questions are original Learnova questions shaped around official content and exam skills.

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