A linear sequence has a constant difference
What you will learn
Know the rule, then use it
These are the short notes. Read each one, then check you can use it in the worked example below.
Method
The common difference d is the step between consecutive terms
Find the common difference
From term 3 to term 8 is 5 steps
Use the nth term form: T(n) = dn + c = 4n + c
We know T(3) = 13, so 4(3) + c = 13
Write the nth term
T(n) = 4n + 1
Watch out
Students confuse the common difference with the nth term itself
A linear sequence has the 3rd term 13 and the 8th term 33. Find the nth term formula.
Find the common difference: From term 3 to term 8 is 5 steps. The difference in values is 33 − 13 = 20.So d = 20 ÷ 5 = 4. The sequence increases by 4 each time.
Use the nth term form: T(n) = dn + c = 4n + c: We know T(3) = 13, so 4(3) + c = 13. This gives 12 + c = 13, so c = 1.
Write the nth term: T(n) = 4n + 1.
Verify with T(8): T(8) = 4(8) + 1 = 33. ✓
T(n) = 4n + 1
Build up to the hardest questions
Do them in order. If you miss a step, read the solution, then redo the question without looking.
WorkedreasoningA linear sequence has the 3rd term 13 and the 8th term 33. Find the nth term formula.
4 marks4 minslinear-sequences-workedShow solution
A linear sequence has the 3rd term 13 and the 8th term 33. Find the nth term formula.
- 1.Find the common difference: From term 3 to term 8 is 5 steps. The difference in values is 33 − 13 = 20.So d = 20 ÷ 5 = 4. The sequence increases by 4 each time.
- 2.Use the nth term form: T(n) = dn + c = 4n + c: We know T(3) = 13, so 4(3) + c = 13. This gives 12 + c = 13, so c = 1.
- 3.Write the nth term: T(n) = 4n + 1.
- 4.Verify with T(8): T(8) = 4(8) + 1 = 33. ✓
T(n) = 4n + 1
- M1: find the common difference
- M1: use the nth term form: t(n) = dn + c = 4n + c
- M1: write the nth term
- M1: verify with t(8)
- A1: T(n) = 4n + 1
Students confuse the common difference with the nth term itself.The common difference is the coefficient of n, not the whole formula.Also, students sometimes write the nth term using n = 1 giving T(1) = 5, then assume the formula is the first term + (n−1)×d, which is equivalent but more error-prone than the dn + c method.Always check by substituting n = 1 and n = 2.
DiagnosticrecallFind the nth term of 3, 7, 11, 15, ...
1 mark2 minslinear-sequences-q1Show solution
Find the nth term of 3, 7, 11, 15, ...
- 1.Spot the skill: The common difference d is the step between consecutive terms.
- 2.Use the find the common difference stage first, then use the nth term form: t(n) = dn + c = 4n + c.
- 3.Keep the final answer visible: 4n − 1.
4n − 1
- M1: use the correct the common difference d is the step between consecutive terms. the nth term has the form dn + c.find d first, then substitute any known term to find c. this works even when you are not given the first term.
- A1: 4n − 1
Students confuse the common difference with the nth term itself.The common difference is the coefficient of n, not the whole formula.Also, students sometimes write the nth term using n = 1 giving T(1) = 5, then assume the formula is the first term + (n−1)×d, which is equivalent but more error-prone than the dn + c method.Always check by substituting n = 1 and n = 2.
EasyprocedureFind the nth term of 20, 17, 14, 11, ...
2 marks3 minslinear-sequences-q2Show solution
Find the nth term of 20, 17, 14, 11, ...
- 1.Spot the skill: The common difference d is the step between consecutive terms.
- 2.Use the use the nth term form: t(n) = dn + c = 4n + c stage first, then write the nth term.
- 3.Keep the final answer visible: −3n + 23.
−3n + 23
- M1: use the correct the common difference d is the step between consecutive terms. the nth term has the form dn + c.find d first, then substitute any known term to find c. this works even when you are not given the first term.
- A1: −3n + 23
Students confuse the common difference with the nth term itself.The common difference is the coefficient of n, not the whole formula.Also, students sometimes write the nth term using n = 1 giving T(1) = 5, then assume the formula is the first term + (n−1)×d, which is equivalent but more error-prone than the dn + c method.Always check by substituting n = 1 and n = 2.
MediumreasoningWhich term of the sequence 5n − 2 equals 98?
3 marks4 minslinear-sequences-q3Show solution
Which term of the sequence 5n − 2 equals 98?
- 1.Spot the skill: The common difference d is the step between consecutive terms.
- 2.Use the write the nth term stage first, then verify with t(8).
- 3.Keep the final answer visible: 20th term.
20th term
- M1: use the correct the common difference d is the step between consecutive terms. the nth term has the form dn + c.find d first, then substitute any known term to find c. this works even when you are not given the first term.
- A1: 20th term
Students confuse the common difference with the nth term itself.The common difference is the coefficient of n, not the whole formula.Also, students sometimes write the nth term using n = 1 giving T(1) = 5, then assume the formula is the first term + (n−1)×d, which is equivalent but more error-prone than the dn + c method.Always check by substituting n = 1 and n = 2.
Hardproblem solvingIs 150 a term in the sequence 4n + 2? Explain.
3 marks5 minslinear-sequences-q4Show solution
Is 150 a term in the sequence 4n + 2? Explain.
- 1.Spot the skill: The common difference d is the step between consecutive terms.
- 2.Use the verify with t(8) stage first, then find the common difference.
- 3.Keep the final answer visible: No — = 37, so T(37) = 150 − 2 = 148, not 150.
No — = 37, so T(37) = 150 − 2 = 148, not 150
- M1: use the correct the common difference d is the step between consecutive terms. the nth term has the form dn + c.find d first, then substitute any known term to find c. this works even when you are not given the first term.
- A1: No — = 37, so T(37) = 150 − 2 = 148, not 150
Students confuse the common difference with the nth term itself.The common difference is the coefficient of n, not the whole formula.Also, students sometimes write the nth term using n = 1 giving T(1) = 5, then assume the formula is the first term + (n−1)×d, which is equivalent but more error-prone than the dn + c method.Always check by substituting n = 1 and n = 2.
Exam-stylemulti-stepTwo sequences are A: 3n + 1 and B: 5n − 3. Find the first term that appears in both sequences.
4 marks6 minslinear-sequences-q5Show solution
Two sequences are A: 3n + 1 and B: 5n − 3. Find the first term that appears in both sequences.
- 1.Spot the skill: The common difference d is the step between consecutive terms.
- 2.Use the find the common difference stage first, then use the nth term form: t(n) = dn + c = 4n + c.
- 3.Keep the final answer visible: T(2) of A = 7; T(2) of B = 7; answer is 7.
T(2) of A = 7; T(2) of B = 7; answer is 7
- M1: use the correct the common difference d is the step between consecutive terms. the nth term has the form dn + c.find d first, then substitute any known term to find c. this works even when you are not given the first term.
- A1: T(2) of A = 7; T(2) of B = 7; answer is 7
Students confuse the common difference with the nth term itself.The common difference is the coefficient of n, not the whole formula.Also, students sometimes write the nth term using n = 1 giving T(1) = 5, then assume the formula is the first term + (n−1)×d, which is equivalent but more error-prone than the dn + c method.Always check by substituting n = 1 and n = 2.
Grade 9 stretchproblem solvingThe nth term of a sequence is 4n - 1. Which term has value 83?
4 marks7 minslinear-sequence-g9Show solution
The nth term of a sequence is 4n - 1. Which term has value 83?
- 1.Set the nth term equal to 83.
- 2.Solve the equation for n.
The 21st term
- M1: form 4n - 1 = 83
- A1: n = 21
Do not rush straight into arithmetic. Select the relevant method and show a complete chain of working.
Switch between skills
Set a timer and attempt all four questions before opening any answers. This is closer to the way skills appear in a real paper.
1Linear sequences - 2 marksFind the nth term of 3, 7, 11, 15, ...Mark answer
4n − 1
2Algebraic notation and substitution - 2 marksFind t² + 4t when t = −2Mark answer
−4
3Simplifying expressions - 2 marksSimplify 2xy + 3x²y − xy + x²yMark answer
3x²y + xy
4Expanding and factorising - 3 marksFactorise fully 6x² + 9xMark answer
3x(2x + 3)
- I can explain the method for linear sequences.
- I can show clear working without skipping key steps.
- I can avoid this mistake: Students confuse the common difference with the nth term itself.The common difference is the coefficient of n, not the whole formula.Also, students sometimes write the nth term using n = 1 giving T(1) = 5, then assume the formula is the first term + (n−1)×d, which is equivalent but more error-prone than the dn + c method.Always check by substituting n = 1 and n = 2.
This guide follows the AQA GCSE Mathematics 8300 specification. Practice questions are original Learnova questions shaped around official content and exam skills.