A function maps each input to an output
What you will learn
Know the rule, then use it
These are the short notes. Read each one, then check you can use it in the worked example below.
Method
f(x) means 'do this operation to x'
Evaluate f(3)
f(3) = 2(3) − 1 = 5
Evaluate f(−2)
f(−2) = 2(−2) − 1 = −5
Find the inverse: write y = 2x − 1
Swap x and y: x = 2y − 1
Watch out
For composite functions, students apply f first then g
f(3) means put 3 into the function f.
fg(x) means apply g first, then f.
Given f(x) = 2x − 1, find f(3), f(−2) and the inverse function f-1(x).
Evaluate f(3): f(3) = 2(3) − 1 = 5.
Evaluate f(−2): f(−2) = 2(−2) − 1 = −5.
Find the inverse: write y = 2x − 1: Swap x and y: x = 2y − 1.
Rearrange for y: 2y = x + 1 → y = (x + 1)/2. So f-1(x) = (x + 1)/2.
f(3) = 5, f(−2) = −5, f-1(x) = (x + 1)/2
Build up to the hardest questions
Do them in order. If you miss a step, read the solution, then redo the question without looking.
WorkedreasoningGiven f(x) = 2x − 1, find f(3), f(−2) and the inverse function f-1(x).
4 marks4 minsfunctions-workedShow solution
Given f(x) = 2x − 1, find f(3), f(−2) and the inverse function f-1(x).
- 1.Evaluate f(3): f(3) = 2(3) − 1 = 5.
- 2.Evaluate f(−2): f(−2) = 2(−2) − 1 = −5.
- 3.Find the inverse: write y = 2x − 1: Swap x and y: x = 2y − 1.
- 4.Rearrange for y: 2y = x + 1 → y = (x + 1)/2. So f-1(x) = (x + 1)/2.
f(3) = 5, f(−2) = −5, f-1(x) = (x + 1)/2
- M1: evaluate f(3)
- M1: evaluate f(−2)
- M1: find the inverse: write y = 2x − 1
- M1: rearrange for y
- A1: f(3) = 5, f(−2) = −5, f-1(x) = (x + 1)/2
For composite functions, students apply f first then g. Remember fg(x) means 'g then f' — work from right to left.Also, the domain of f-1 may differ from f's domain; flag any restrictions.
DiagnosticrecallGiven g(x) = x2 + 1, find g(−3).
1 mark2 minsfunctions-q1Show solution
Given g(x) = x2 + 1, find g(−3).
- 1.Spot the skill: f(x) means 'do this operation to x'.
- 2.Use the evaluate f(3) stage first, then evaluate f(−2).
- 3.Keep the final answer visible: 10.
10
- M1: use the correct f(x) means 'do this operation to x'. substitute directly for f(a).composite fg(x) means apply g first, then f.inverse f-1 reverses f: write y = f(x), swap x and y, rearrange for the new y.
- A1: 10
For composite functions, students apply f first then g. Remember fg(x) means 'g then f' — work from right to left.Also, the domain of f-1 may differ from f's domain; flag any restrictions.
EasyprocedureFind fg(2) where f(x) = 3x and g(x) = x + 4.
2 marks3 minsfunctions-q2Show solution
Find fg(2) where f(x) = 3x and g(x) = x + 4.
- 1.Spot the skill: f(x) means 'do this operation to x'.
- 2.Use the evaluate f(−2) stage first, then find the inverse: write y = 2x − 1.
- 3.Keep the final answer visible: f(g(2)) = f(6) = 18.
f(g(2)) = f(6) = 18
- M1: use the correct f(x) means 'do this operation to x'. substitute directly for f(a).composite fg(x) means apply g first, then f.inverse f-1 reverses f: write y = f(x), swap x and y, rearrange for the new y.
- A1: f(g(2)) = f(6) = 18
For composite functions, students apply f first then g. Remember fg(x) means 'g then f' — work from right to left.Also, the domain of f-1 may differ from f's domain; flag any restrictions.
MediumreasoningFind the inverse of h(x) = (x − 3)/5.
3 marks4 minsfunctions-q3Show solution
Find the inverse of h(x) = (x − 3)/5.
- 1.Spot the skill: f(x) means 'do this operation to x'.
- 2.Use the find the inverse: write y = 2x − 1 stage first, then rearrange for y.
- 3.Keep the final answer visible: h-1(x) = 5x + 3.
h-1(x) = 5x + 3
- M1: use the correct f(x) means 'do this operation to x'. substitute directly for f(a).composite fg(x) means apply g first, then f.inverse f-1 reverses f: write y = f(x), swap x and y, rearrange for the new y.
- A1: h-1(x) = 5x + 3
For composite functions, students apply f first then g. Remember fg(x) means 'g then f' — work from right to left.Also, the domain of f-1 may differ from f's domain; flag any restrictions.
Hardproblem solvingSolve f(x) = 11 where f(x) = 4x − 1.
3 marks5 minsfunctions-q4Show solution
Solve f(x) = 11 where f(x) = 4x − 1.
- 1.Spot the skill: f(x) means 'do this operation to x'.
- 2.Use the rearrange for y stage first, then evaluate f(3).
- 3.Keep the final answer visible: x = 3.
x = 3
- M1: use the correct f(x) means 'do this operation to x'. substitute directly for f(a).composite fg(x) means apply g first, then f.inverse f-1 reverses f: write y = f(x), swap x and y, rearrange for the new y.
- A1: x = 3
For composite functions, students apply f first then g. Remember fg(x) means 'g then f' — work from right to left.Also, the domain of f-1 may differ from f's domain; flag any restrictions.
Exam-stylemulti-stepGiven f(x) = x2 − 1 and g(x) = 2x, find gf(3).
4 marks6 minsfunctions-q5Show solution
Given f(x) = x2 − 1 and g(x) = 2x, find gf(3).
- 1.Spot the skill: f(x) means 'do this operation to x'.
- 2.Use the evaluate f(3) stage first, then evaluate f(−2).
- 3.Keep the final answer visible: g(f(3)) = g(8) = 16.
g(f(3)) = g(8) = 16
- M1: use the correct f(x) means 'do this operation to x'. substitute directly for f(a).composite fg(x) means apply g first, then f.inverse f-1 reverses f: write y = f(x), swap x and y, rearrange for the new y.
- A1: g(f(3)) = g(8) = 16
For composite functions, students apply f first then g. Remember fg(x) means 'g then f' — work from right to left.Also, the domain of f-1 may differ from f's domain; flag any restrictions.
Grade 9 stretchproblem solvingGiven f(x) = (2x - 3)/(x + 1), x != -1, find f-1(x) and solve f-1(x) = 5.
4 marks7 minsfunctions-g9Show solution
Given f(x) = (2x - 3)/(x + 1), x != -1, find f-1(x) and solve f-1(x) = 5.
- 1.Write y = (2x - 3)/(x + 1) and make x the subject.
- 2.Swap x and y to state the inverse function.
- 3.Solve the inverse equation and check the value is in its domain.
f-1(x) = (x + 3)/(2 - x), x != 2; solving f-1(x) = 5 gives x =
- M1: obtain yx + y = 2x - 3
- M1: rearrange to x = (y + 3)/(2 - y)
- A1: state the inverse with x != 2
- A1: solve (x + 3)/(2 - x) = 5 to get x =
Do not rush straight into arithmetic. Select the relevant method and show a complete chain of working.
Switch between skills
Set a timer and attempt all four questions before opening any answers. This is closer to the way skills appear in a real paper.
1Functions - 2 marksGiven g(x) = x2 + 1, find g(−3).Mark answer
10
2Algebraic notation and substitution - 2 marksFind t² + 4t when t = −2Mark answer
−4
3Simplifying expressions - 2 marksSimplify 2xy + 3x²y − xy + x²yMark answer
3x²y + xy
4Expanding and factorising - 3 marksFactorise fully 6x² + 9xMark answer
3x(2x + 3)
- I can explain the method for functions.
- I can show clear working without skipping key steps.
- I can avoid this mistake: For composite functions, students apply f first then g.Remember fg(x) means 'g then f' — work from right to left.Also, the domain of f-1 may differ from f's domain; flag any restrictions.
This guide follows the AQA GCSE Mathematics 8300 specification. Practice questions are original Learnova questions shaped around official content and exam skills.